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cURL没有用PHP显示整个GET参数

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这是我用来向我的应用发送通知的代码 .

include("connection.php");
    include("utils.php");

    $Info = mysql_fetch_array(mysql_query("SELECT * FROM data WHERE iddata = ".$_GET["dataId"]));
    $ownerInfo = mysql_fetch_array(mysql_query("SELECT * FROM dataUsers WHERE id = ".$dataInfo['id']));
    $data = mysql_fetch_array(mysql_query("SELECT dataUsers.id, dataUsers.token, data.idData, data.id FROM data INNER JOIN data ON data.iddata = '".$_GET["data"]."' AND data.id = dataUsers.id"))["token"];

    $datagOwnerDeviceToken = getDeviceTokenFromUserToken($dataOwnerToken);
    //call server where simplePush.php is located -ports opened-
    $curl = curl_init();
    curl_setopt_array($curl, array(
        CURLOPT_RETURNTRANSFER => 1,
        CURLOPT_URL => "http://www.myserver.com/sendNotif.php?msg=hello guys&deviceToken=xxxxxxxxxxxx",
        CURLOPT_USERAGENT => 'whatever'
        ));

        $resp = curl_exec($curl);
        curl_close($curl);

问题是我收到了通知，但我没有收到“你好”，我收到“你好”，也就是说，当它找到一个空格时，字符串会被删除 . 我认为这可能是由于编码，但我真的不知道如何使其工作 .

如果我将msg参数更改为msg = helloguys，我会收到整个字符串 . 所以空格有问题 .

非常感谢 .

这是现在的实际代码：

$curl = curl_init();

curl_setopt_array（$ curl，array（CURLOPT_RETURNTRANSFER => 1，

$url = "http://server.com/notifications.php?".http_build_query(array(
    'msg' => "hello this is ".$dataInfo["wastringText"],
    'deviceToken' => $dataOwnerDeviceToken
));

echo "This is my url: " . $ url; curl_setopt_array（$卷曲，阵列（CURLOPT_RETURNTRANSFER => 1，CURLOPT_URL => $网址，CURLOPT_USERAGENT => 'whatever'））;
$ resp = curl_exec（$ curl）; curl_close（$卷曲）;

php curl encoding get

1 回答

  • 0

    您需要将空间编码为 %20 或 + . 但最好使用 http_build_query 来编码整个查询字符串 .

    $url = "http://www.myserver.com/sendNotif.php?" . 
    http_build_query(array(
        'msg' => 'hello guys',
        'deviceToken' => 'xxxxxxxxxxxx'
    ));
curl_setopt_array($curl, array(
    CURLOPT_RETURNTRANSFER => 1,
    CURLOPT_URL => $url,
    CURLOPT_USERAGENT => 'whatever'
    ));
    回复于

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